A) 120 V and 100 Hz
B) \[\frac{120}{\sqrt{2}}V\]and 100 Hz
C) 60 V and 200 Hz
D) 60 V and 100 Hz
Correct Answer: D
Solution :
(d) 60 V and 100 Hz \[V=120\,\sin \,\,(100\pi t)\,\,cos\,\,(100\,\pi t)V\] \[=60\,\sin \,(200\pi t)V(\because \,sin\,2\theta =2sin\theta cos\theta )\]Compare it with standard equation, \[V={{V}_{0}}\sin \,\omega t\] We get. \[{{V}_{0}}=60\,V\] and \[\omega =200\pi \] or \[2\pi v=200\pi \] or \[v=100\,Hz\]
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