A) \[284\,\Omega \]
B) \[384\,\Omega \]
C) \[484\,\Omega \]
D) \[584\,\Omega \]
Correct Answer: C
Solution :
(c) \[484\,\Omega \] Here, \[P=100\,W,\,{{V}_{rms}}=220\,V\] Resistance of the bulb is \[R=\frac{V_{rms}^{2}}{P}=\frac{{{(220)}^{2}}}{100}=484\,\Omega \]
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