A) \[V(t)={{V}_{m}}{{e}^{\omega t}}\]
B) \[V(t)={{V}_{m}}\sin \,\omega t\]
C) \[V(t)={{V}_{m}}\cot \,\omega t\]
D) \[V(t)={{V}_{m}}tan\,\omega t\] where \[{{V}_{m}}\] is the peak voltage
Correct Answer: B
Solution :
(b) \[V(t)={{V}_{m}}\sin \,\omega t\] The equation of alternating voltage is \[V(t)={{V}_{m}}\sin \,\omega t\]
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