A) 12.8 A
B) 13.6 A
C) 15.9A
D) 19.5 A
Correct Answer: C
Solution :
(c) 15.9 A Here, \[L=44\,mH=44\times {{10}^{-3}}H\] \[{{V}_{rms}}=220\,V,\,v=50\,Hz\] The inductive reactance is \[{{X}_{L}}=\omega L=2\pi vL\] \[=2\times 3.14\times 50\times 44\times {{10}^{-3}}=13.82\,\Omega \] \[\therefore {{l}_{rms}}=\frac{{{V}_{rms}}}{{{X}_{L}}}=\frac{220}{13.82}=15.9\,A\]
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