A) 129.4 V
B) 12.94 V
C) 1.294 V
D) 15 V
Correct Answer: B
Solution :
(b) 12.94 V Here, \[{{V}_{rms}}=220\,\,V,\,\,{{l}_{rms}}=65\,mA=0.065\,A\] \[C=8\mu F=8\times {{10}^{-6}}F,v=100\,Hz\] Capacitive reactance, \[{{X}_{C}}=\frac{1}{2\pi vC}\] \[=\frac{1}{2\times 3.14\times 100\times 8\times {{10}^{-6}}}=199\,\Omega \] rms voltage across the capacitor is \[{{V}_{rms}}={{l}_{rms}}{{X}_{C}}=0.065\times 199=12.94\,V\]
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