A) 8 W
B) 12 W
C) 14.4 W
D) 18 W
Correct Answer: C
Solution :
(c) 14.4 W Here, \[{{X}_{L}}=1\,\Omega ,\,R=2\,\Omega ,\,{{V}_{rms}}=6V\] Impedance of the circuit \[Z=\sqrt{X_{L}^{2}+{{R}^{2}}}=\sqrt{{{(1)}^{2}}+{{(2)}^{2}}}=\sqrt{5}\,\Omega \] \[{{l}_{rms}}=\frac{{{V}_{rms}}}{Z}=\frac{6}{\sqrt{5}}A\] Power dissipated \[P={{V}_{rms}}{{l}_{rms}}\cos \phi ={{V}_{rms}}{{l}_{rms}}\frac{R}{Z}\] \[=6\times \frac{6}{\sqrt{5}}\times \frac{2}{\sqrt{5}}=\frac{72}{5}=14.4\,\,W\]
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