A) 100 V
B) 200 V
C) 400 V
D) 10 V
Correct Answer: C
Solution :
(c) 400 V Here, \[{{V}_{rms}}=200\,V,\,{{X}_{L}}=50\,\Omega ,\,{{X}_{C}}=50\,\Omega \,R=25\,\Omega \] Impedance of the circuit. \[Z=\sqrt{{{R}^{2}}+{{\left( {{X}_{L}}-{{X}_{C}} \right)}^{2}}}\] \[=\sqrt{{{25}^{2}}+{{(50-50)}^{2}}}=25\,\Omega \] Current in the circuit, \[{{l}_{rms}}=\frac{{{V}_{rms}}}{Z}=\frac{200\,V}{25\,\Omega }=8\,A\] Voltage drop across the inductor is \[{{V}_{L}}={{l}_{rms}}{{X}_{L}}=8\,A\times 50\,\Omega =400\,V\]
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