12th Class Physics Alternating Current / प्रत्यावर्ती धारा Question Bank MCQ - Alternating Currents

  • question_answer
    A \[100\text{ }\mu \text{F}\] capacitor is in series with a \[40\,\Omega \]. resistor, connected to a 100V, 60Hz supply. The time lag between the current maximum and the voltage maximum is:

    A) 15.5 ms                        

    B) 155 ms

    C) 1.55 ms                        

    D) 1.55 s

    Correct Answer: C

    Solution :

    (c) 1.55 ms In series RC circuit voltage lags behind the current by phase angle \[\phi \]. Then,   \[\tan \,\phi =\frac{{{X}_{C}}}{R}=\frac{1/\omega C}{R}=\frac{1}{\omega CR}=\frac{1}{2\pi vCR}\] \[\tan \,\phi =\frac{1}{2\pi \times 60\times {{10}^{-4}}\times 40}\] \[\tan \,\phi =(0.6634);\phi =ta{{n}^{-1}}(0.6634)\]             \[=33.56{}^\circ =33.56\times \frac{\pi }{180}rad\] \[\therefore \] Time lag, \[\Delta T=\frac{\phi }{\omega }\]             \[=\frac{\frac{33.56\times \pi }{180}}{120\pi }=1.55\times {{10}^{-3}}s=1.55\,ms\]                                     \[[\because \,\omega =2\pi v=120\,\pi ]\]


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