12th Class Physics Alternating Current / प्रत्यावर्ती धारा Question Bank MCQ - Alternating Currents

  • question_answer
    An alternating voltage given by \[V=140\,\,sin\,\,314t\]is connected across a pure resistor of \[50\text{ }\Omega \], the rms current through the resistor is:

    A) 1.98 A                          

    B) 5.63 A

    C) 8.43 A                          

    D) 2.39 A

    Correct Answer: A

    Solution :

    (a) 1.98 A Here,   \[R=50\,\Omega ,\,\,Vo=140\,V\] \[\therefore {{l}_{rms}}=\frac{{{V}_{rms}}}{R}=\frac{0.707\,{{V}_{0}}}{R}\]             \[=\frac{0.707\times 140}{50}=1.98\,A\]


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