A) 200 W
B) 2000 W
C) 100 W
D) 4000 W
Correct Answer: B
Solution :
(b) 2000 W If the frequency of an AC source equals the natural frequency of the circuit, the impedance \[Z=R=20\,\Omega \] The average power dissipated per cycle, \[{{P}_{av}}=\frac{V_{rms}^{2}}{Z}=\frac{V_{rms}^{2}}{R}=\frac{{{(200)}^{2}}}{20}=2000\,W\]You need to login to perform this action.
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