A) 0.1 H
B) 0.064 H
C) 2 H
D) 5 H
Correct Answer: B
Solution :
(b) 0.064 H Quality factor, \[Q=\frac{1}{R}\sqrt{\frac{1}{C}}\] or \[\frac{L}{C}={{(QR)}^{2}}\] Here, \[Q=0.4,\,\,R=2\,k\Omega =2\times {{10}^{3}}\Omega \] \[C=0.1\mu F=0.1\times {{10}^{-6}}F\] \[\therefore L={{(QR)}^{2}}C\] \[\therefore \,\,\,\,\,\,\,L={{(0.4\times 2\times {{10}^{3}})}^{2}}\times 0.1\times {{10}^{-6}}=0.064\,H\]
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