A) 51.5
B) 50.7
C) 51.1
D) 50.3
Correct Answer: D
Solution :
(d) 50.3 Here, \[{{V}_{0}}=283\,\,V,\,\,R=3\,\Omega ,\,L=25\times {{10}^{-3}}H\] \[C=400\,\mu F=4\times {{10}^{-4}}F\] Maximum power is dissipated at resonance, for which \[v=\frac{1}{2\pi \sqrt{LC}}=\frac{1\times 7}{2\times 22\sqrt{25\times {{10}^{-3}}\times 4\times {{10}^{-4}}}}\] \[=\frac{7\times {{10}^{3}}}{44\sqrt{10}}=50.3\,Hz\]You need to login to perform this action.
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