A) remains same
B) doubled
C) halved
D) zero
Correct Answer: C
Solution :
(c) halved Capacitive reactance, \[{{X}_{C}}=\frac{1}{2\pi vC}\] \[\Rightarrow {{X}_{C}}\propto \frac{1}{v}\] \[\therefore \frac{{{X}_{{{C}_{1}}}}}{{{X}_{{{C}_{2}}}}}=\frac{{{v}_{2}}}{{{v}_{1}}}=\frac{2v}{v}=2\] \[\Rightarrow {{x}_{{{c}_{2}}}}=\frac{{{X}_{{{C}_{1}}}}}{2}\]You need to login to perform this action.
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