A) 15.5 ms
B) 155 ms
C) 1.55 ms
D) 1.55 s
Correct Answer: C
Solution :
(c) 1.55 ms In series RC circuit voltage lags behind the current by phase angle \[\phi \]. Then, \[\tan \,\phi =\frac{{{X}_{C}}}{R}=\frac{1/\omega C}{R}=\frac{1}{\omega CR}=\frac{1}{2\pi vCR}\] \[\tan \,\phi =\frac{1}{2\pi \times 60\times {{10}^{-4}}\times 40}\] \[\tan \,\phi =(0.6634);\phi =ta{{n}^{-1}}(0.6634)\] \[=33.56{}^\circ =33.56\times \frac{\pi }{180}rad\] \[\therefore \] Time lag, \[\Delta T=\frac{\phi }{\omega }\] \[=\frac{\frac{33.56\times \pi }{180}}{120\pi }=1.55\times {{10}^{-3}}s=1.55\,ms\] \[[\because \,\omega =2\pi v=120\,\pi ]\]You need to login to perform this action.
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