A) 1.2 V and 1.5 V respectively
B) 2.1 V and 2.2 V respectively
C) 1.3 V and 1.2 V respectively
D) 5.1 V and 5.2 V respectively
Correct Answer: C
Solution :
(c) 1.3 V and 1.2 V respectively We know that. \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{l}_{1}}}{{{l}_{2}}}\] According to question, \[{{E}_{2}}={{E}_{1}}-0.1\] \[\therefore \frac{{{E}_{1}}}{{{E}_{1}}-0.1}=\frac{65}{60}\] \[\frac{{{E}_{1}}}{{{E}_{1}}-0.1}=\frac{13}{12}\] \[12{{E}_{1}}=13{{E}_{1}}-1.3\] \[{{E}_{1}}=+1.3\,V\] \[{{E}_{2}}=1.3-0.1=1.2\,V\]
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