A) 3.05 V
B) 2.05 V
C) 4.05 V
D) 6.05 V
Correct Answer: A
Solution :
(a) 3.05 V Here, in the balance condition of potentiometer \[\frac{{{\varepsilon }_{1}}}{{{\varepsilon }_{2}}}=\frac{{{l}_{1}}}{{{l}_{2}}}\] Or \[{{\varepsilon }_{1}}=1.5\,V,{{l}_{1}}=32\,cm,{{l}_{2}}=65\,cm\] \[\therefore {{\varepsilon }_{2}}={{\varepsilon }_{1}}\times \frac{{{l}_{2}}}{{{l}_{1}}}=1.5\times \frac{65}{32}=3.05\,V\]
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