A) \[2.2\,mA\]
B) \[2.2\sqrt{2}\,mA\]
C) \[\frac{2.2}{\sqrt{2}}\,mA\]
D) None of these
Correct Answer: A
Solution :
(a) 2.2 mA As, V=IR \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,l=\frac{V}{R}=\frac{220}{100\times {{10}^{3}}}\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,l=2.2\times {{10}^{-3}}A=2.2\,mA\]
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