A)
B)
C)
D)
Correct Answer: B
Solution :
(b) Current in the circuit, \[l=\frac{\varepsilon }{R+r}\] Potential difference across R, \[V=lR=\left( \frac{\varepsilon }{R+r} \right)R=\frac{\varepsilon }{\left( 1+\frac{r}{R} \right)}\] When \[R=0,=0\,\,or\,\,R=\infty ,V=\varepsilon \]You need to login to perform this action.
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