A) 5E
B) 2E
C) 3E
D) 4E
Correct Answer: C
Solution :
(c) 3E Emf of the 5 identical cells of emf E are connected in series. Then the net emf of the combination should be 5E. But, one of them is wrongly connected i.e., with its polarity reversed. This cell will cancel the emf of another cell. Thus, equivalent number of cells in the combination =E+E+E+E-E=3E. Net emf of the combination = 3E.You need to login to perform this action.
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