A) 2
B) 1.25
C) 0.4
D) 1.2
Correct Answer: D
Solution :
(d) 1.2 The current = \[\frac{\text{net}\,\,\text{emf}}{\text{net}\,\,\text{resistance}}\] \[\text{l=}\frac{2+2+2}{1+1+1+2}\] \[=\frac{6}{5}\] \[=1.2\,A\]You need to login to perform this action.
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