A) 40 C
B) 48 C
C) 38 C
D) 43 C
Correct Answer: B
Solution :
(b) 48 C Let dq be the charge which passes in a small interval on time dt. Then \[dp=ldt\]or \[dp=\left( 4+2t \right)\,dt\] On integrating, we get \[q=\int_{2}^{6}{\left( 4+2t \right)}\,dt=\left[ 4t+{{t}^{2}} \right]_{2}^{6}=48C\]
You need to login to perform this action.
You will be redirected in
3 sec
