A) R
B) 2R
C) \[\frac{R}{2}\]
D) \[\frac{R}{4}\]
Correct Answer: A
Solution :
(a) R As \[\frac{P}{Q}=\frac{R}{S}\], so resistance of the galvanometer can be omitted (P and Q are in series = 2R, R and S are also in series = 2R). Now the equivalent resistance \[=\frac{2R\times 2R}{4R}=R\].You need to login to perform this action.
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