A) \[180{}^\circ ,\,\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{Q}^{2}}}{{{\left( 2L \right)}^{2}}}\]
B) \[90{}^\circ ,\,\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{Q}^{2}}}{{{L}^{2}}}\]
C) \[180{}^\circ ,\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{Q}^{2}}}{2{{L}^{2}}}\]
D) \[180{}^\circ ,\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{Q}{4L}\]
Correct Answer: A
Solution :
\[180{}^\circ ,\,\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{Q}^{2}}}{{{\left( 2L \right)}^{2}}}\] In a satellite, there is a condition of weightlessness. \[\therefore \,\,\,\,mg=0\] Due to electrostatic force of repulsion between the balls, the string would become horizontal. \[\therefore\] Angle between string \[=180{}^\circ\] Tension in string = Force of repulsion \[=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{Q}{{{\left( 2L \right)}^{2}}}\]
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