A) \[1.8\times {{10}^{-10}}N{{C}^{-1}}\]
B) \[1.9\times {{10}^{-10}}N{{C}^{-1}}\]
C) \[1.6\times {{10}^{-10}}N{{C}^{-1}}\]
D) \[1.5\times {{10}^{-10}}N{{C}^{-1}}\]
Correct Answer: A
Solution :
\[1.8\times {{10}^{-10}}N{{C}^{-1}}\] Here, \[E=\frac{\sigma }{{{\varepsilon }_{0}}}=\frac{16\times {{10}^{-22}}}{8.854\times {{10}^{-12}}}\] \[=1.8\times {{10}^{-10}}N{{C}^{-1}}\]You need to login to perform this action.
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