A) -1.6C
B) +1.6C
C) \[{{10}^{19}}C\]
D) \[{{10}^{-19}}C\]
Correct Answer: B
Solution :
(b) +1.6C Charge of one electron, \[e=-1.6\times {{10}^{-19}}C\] So, total charge removed from neutral plate, Q = ne \[={{10}^{19}}\times \left( -1.6\times {{10}^{-19}} \right)\] \[=-1.6\,C\] Since, charge on neutral plate is zero and -1.6C charge is removed from it. Thus, now it has +1.6 C charge.
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