A) \[5.2\times {{10}^{-4}}\,N\]
B) \[2.5\times {{10}^{-3}}N\]
C) \[1.5\times {{10}^{-3}}\,N\]
D) \[3.5\times {{10}^{-4}}N\]
Correct Answer: B
Solution :
(b) \[2.5\times {{10}^{-3}}N\] Here,\[{{q}_{1}}={{q}_{2}}=3.2\times {{10}^{-7}}\], \[r=60\,cm=0.6\,m\] Electrostatic force, \[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\] \[=\frac{\left( 9\times {{10}^{9}} \right){{\left( 3.2\times {{10}^{-7}} \right)}^{2}}}{{{\left( 0.6 \right)}^{2}}}\] \[=2.56\times {{10}^{-3}}N\]You need to login to perform this action.
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