A) \[2.5\times {{10}^{9}}\]
B) \[1.5\times {{10}^{19}}\]
C) \[1.5\times {{10}^{19}}\]
D) \[2.5\times {{10}^{-19}}\]
Correct Answer: B
Solution :
(b) \[1.5\times {{10}^{19}}\] Total charge, \[q\text{ }=\text{ }+\text{ }2.4\text{ }C\] Then by quantisation of charge, q = ne \[\therefore \]Number of electrons, \[n=\frac{q}{e}\] \[=\frac{2.4\,C}{1.6\times {{10}^{-19}}C}=15\times {{10}^{19}}\]
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