A) \[4.5\times {{10}^{-2}}\,N\]
B) \[4.5\times {{10}^{-3}}N\]
C) \[5.4\times {{10}^{-2}}N\]
D) \[5.4\times {{10}^{-3}}N\]
Correct Answer: B
Solution :
(b) \[4.5\times {{10}^{-3}}N\] Here, \[{{q}_{1}}=1\times {{10}^{-7}}C\], \[{{q}_{2}}=2\times {{10}^{-7}}\,C.\] \[r=20\,cm\,=20\times {{10}^{-2}}m\] As \[F=\frac{{{q}_{1}}{{q}_{2}}}{4\pi {{\varepsilon }_{0}}{{r}^{2}}}\] \[=\frac{9\times {{10}^{9}}\times 1\times {{10}^{-7}}\times 2\times {{10}^{-7}}}{{{\left( 20\times {{10}^{-2}} \right)}^{2}}}\] \[=4.5\times {{10}^{-3}}\,N\]
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