A) 20.6N
B) 25.6N
C) 15.6N
D) 12.6N
Correct Answer: B
Solution :
(b) 25.6 N Charge of proton is, \[{{q}_{p}}=1.6\times {{10}^{-19}}\,C\] Distance between the protons is, \[r=3\times {{10}^{-15}}m\] The magnitude of electrostatic force between protons is \[{{F}_{e}}=\frac{{{q}_{p}}{{q}_{p}}}{4\pi {{\varepsilon }_{0}}{{r}^{2}}}\] \[=\frac{9\times {{10}^{19}}\times 1.6\times {{10}^{-19}}\times 1.6\times {{10}^{-19}}}{{{\left( 3\times {{10}^{-15}} \right)}^{2}}}\] =25.6N
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