A) 2N
B) 4N
C) 5N
D) 7.5N
Correct Answer: C
Solution :
(c) 5 N Here, \[{{q}_{1}}=+3\mu C,\,{{q}_{2}}=+4\,\mu C,\,F=10\,N\] \[q{{'}_{1}}=+3-6=-3\mu C,\] \[q{{'}_{2}}=+4-6=-2\mu C\] \[\therefore \,\,\,\,\,\frac{F'}{F}=\frac{\left( q{{'}_{1}} \right)\left( q{{'}_{2}} \right)}{{{q}_{1}}{{q}_{2}}}\] \[=\frac{\left( -3 \right)\times \left( -2 \right)}{3\times 4}=\frac{6}{12}=\frac{1}{2}\] \[\therefore \,\,\,\,F'=\frac{1}{2}\times F=\frac{1}{2}\times 10=5N\]
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