A) \[1.6\times {{10}^{-19}}m{{s}^{2}}\]
B) \[9.1\times {{10}^{31}}m{{s}^{-2}}\]
C) \[1.5\times {{10}^{19}}m{{s}^{-2}}\]
D) \[1.6\times {{10}^{27}}m{{s}^{-2}}\]
Correct Answer: C
Solution :
(c) \[1.5\times {{10}^{19}}m{{s}^{-2}}\] The acceleration due to given coulombic force F is \[a=\frac{F}{m}\] or \[a\propto \frac{1}{m}\] where \[{{m}_{e}}\] and \[{{m}_{p}}\]are masses of electron and proton respectively. \[{{a}_{p}}=\frac{{{a}_{e}}{{m}_{e}}}{{{m}_{p}}}\] \[=\frac{\left( 2.5\times {{10}^{22}}\,m{{s}^{-2}} \right)\left( 9.1\times {{10}^{-31}}kg \right)}{\left( 1.67\times {{10}^{-27}}kg \right)}\] \[=13.6\times {{10}^{18}}m{{s}^{-2}}\approx 1.5\times {{10}^{19}}m{{s}^{-2}}\]
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