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12th Class Physics Electric Charges and Fields Question Bank MCQ - Electric Charges and Fields

  • question_answer
    Each of the two points charges are doubled and their distance is halved. Force of interaction becomes n times, where n is:

    A) 4                     

    B) 1        

    C) 1/16                             

    D) 16

    Correct Answer: D

    Solution :

    (d) 16 From the formula, \[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\] \[F'=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{2{{q}_{1}}\times 2{{q}_{2}}}{{{\left( r/2 \right)}^{2}}}=\frac{4}{1/4}F=16F\] \[\Rightarrow \,nF=16F\Rightarrow n=16\]


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