A) \[2.8\,C\]
B) \[6.4\times {{10}^{-2}}C\]
C) \[3.6\times {{10}^{-3}}C\]
D) \[9.2\times {{10}^{-4}}C\]
Correct Answer: B
Solution :
(b) \[6.4\times {{10}^{-2}}C\] Here, Number of electrons removed = Number of atoms in 1 g or \[n=\frac{4\times {{10}^{20}}}{{{10}^{3}}}=4\times {{10}^{17}}\] \[\therefore \]Charge, q = ne \[=4\times {{10}^{17}}\times 1.6\times {{10}^{-19}}C\] \[=6.4\times {{10}^{-2}}C\]You need to login to perform this action.
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