A) \[-\frac{Q}{2}\]
B) \[-\frac{Q}{4}\]
C) \[\frac{Q}{4}\]
D) \[\frac{Q}{2}\]
Correct Answer: B
Solution :
(b) \[-\frac{Q}{4}\] At equilibrium, net force will be zero \[\therefore \,\,\frac{1}{4\pi {{\varepsilon }_{0}}}\times \frac{Qq}{{{\left( r/2 \right)}^{2}}}+\frac{1}{4\pi {{\varepsilon }_{0}}}\times \frac{{{Q}^{2}}}{{{r}^{2}}}=0\] \[4q=-Q\] Or \[q=\frac{-Q}{4}\]
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