A) half
B) double
C) unchanged
D) thrice
Correct Answer: B
Solution :
(b) double, As \[E=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{{{r}^{2}}}\] If \[q'=2q\], then \[E'=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{2q}{{{r}^{2}}}\] or \[E'=2E\] So, electric field is doubled.
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