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12th Class Physics Electric Charges and Fields Question Bank MCQ - Electric Charges and Fields

  • question_answer
    A force of 2.25 N acts on a charge of \[15\times {{10}^{-4}}C.\] The intensity of electric field at that point is:

    A) \[150\,N{{C}^{-1}}\]               

    B) \[15\,N{{C}^{-1}}\]

    C) \[1500\,N{{C}^{-1}}\]             

    D) \[1.5\,N{{C}^{-1}}\]

    Correct Answer: C

    Solution :

    (c) \[1500\,N{{C}^{-1}}\] Electric field, \[E=\frac{F}{q}=\frac{2.25N}{15\times {{10}^{-4}}C}=1500N{{C}^{-1}}\]


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