12th Class Physics Electro Magnetic Induction Question Bank MCQ - Electromagnetic Induction

  • question_answer
    The self inductance of an inductor coil having 100 turns is 20 mH. The magnetic flux through the cross-section of the coil corresponding to a current of 4 mA is:

    A) \[2\times {{10}^{-5}}Wb\]                   

    B) \[4\times {{10}^{-7}}Wb\]

    C) \[8\times {{10}^{-7}}Wb\]                   

    D) \[8\times {{10}^{-5}}Wb\]

    Correct Answer: C

    Solution :

    (c) \[8\times {{10}^{-7}}Wb\] Total magnetic flux. \[N\phi =Ll=20\times {{10}^{-3}}\times 4\times {{10}^{-3}}\]             \[=8\times {{10}^{-5}}Wb\] Magnetic flux through the cross-section of the coil, \[\phi =\frac{8\times {{10}^{-5}}}{N}=\frac{8\times {{10}^{-5}}}{100}=8\times {{10}^{-7}}Wb\]


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