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12th Class Physics Electro Magnetic Induction Question Bank MCQ - Electromagnetic Induction

  • question_answer
    A small piece of metal wire is dragged across the gap between the poles of a magnet in 0.4 s. If change in magnetic flux in the wire is \[8\times {{10}^{-4}}Wb\], then e.m.f. induced in the wire is:

    A) \[8\times {{10}^{-3}}V\]                      

    B) \[6\times {{10}^{-3}}V\]

    C) \[4\times {{10}^{-3}}V\]                      

    D) \[2\times {{10}^{-3}}V\]

    Correct Answer: D

    Solution :

    (d) \[2\times {{10}^{-3}}V\]                         \[\varepsilon =\frac{d\phi }{dt}\frac{8\times {{10}^{-4}}}{0.4}=2\times {{10}^{-3}}V\]


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