A) 160 V
B) 250 V
C) 270 V
D) 320 V
Correct Answer: A
Solution :
(a) 160 V Here, \[A=0.4\text{ }{{m}^{2}}\text{, }N=100,\text{ }dB=0.04\text{ }Wb\,{{m}^{-2}},\] \[dt=0.01\text{ }s\] As \[\varepsilon =\frac{d\phi }{dt}=NA\frac{dB}{dt}=100\times 0.4\times \frac{0.04}{0.01}=160\,V\]You need to login to perform this action.
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