A) \[4.125\,\,V\]
B) \[3.125\,\,V\]
C) \[2.225\text{ }V\]
D) \[3.8\text{ }V\]
Correct Answer: B
Solution :
(b) \[3.125\,\,V\] Here, \[v=1800\text{ }km\text{ }{{h}^{-1}}=1800\times \frac{5}{18}=500\text{ }m/s\] \[l=25\,m\,{{B}_{H}}=5\times {{10}^{-4}}T,\delta =30{}^\circ \] \[\varepsilon ={{B}_{v}}{{l}_{v}}\], where \[{{B}_{v}}\]= vertical component of earth magnetic field \[=\left( {{B}_{H}}\sin \,\delta \right)lv\] \[=5\times {{10}^{-4}}\times sin\,\,30{}^\circ \times 25\times 500\] \[=31250\times {{10}^{-4}}=3.125\,\,V\]You need to login to perform this action.
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