A) increased by 4
B) decreased by 4
C) remain the same
D) increased by 2
Correct Answer: C
Solution :
(c) remain the same We know that, \[L={{\mu }_{0}}{{n}^{2}}Al\] \[n'=2n\] and \[l'=\frac{l}{4}\] \[\therefore L'={{\mu }_{0}}{{(2n)}^{2}}A\left( \frac{l}{4} \right)\] \[={{\mu }_{0}}4{{n}^{2}}A\left( \frac{l}{4} \right)={{\mu }_{0}}{{n}^{2}}Al=L\]You need to login to perform this action.
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