12th Class Physics Electro Magnetic Induction Question Bank MCQ - Electromagnetic Induction

  • question_answer
    An aeroplane having a wing span of 35 m flies due north with the speed of 90 m/s. If the magnetic field \[B=4\times {{10}^{-5}}T\] then, the potential difference developed between the tip of the wings is:

    A) 1.26 V                          

    B) 1.03 V   

    C) 12.6 V                          

    D) 0.126 V 

    Correct Answer: D

    Solution :

    (d) 0.126 V Potential difference developed = Blv \[=4\times {{10}^{-5}}\times 35\times 90\] \[=12600\times {{10}^{-5}}\] \[=0.126\,V\]


You need to login to perform this action.
You will be redirected in 3 sec spinner