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12th Class Physics Electro Magnetic Induction Question Bank MCQ - Electromagnetic Induction

  • question_answer
    A jet plane is travelling west at the speed of \[1800\text{ }km\text{ }{{h}^{-1}}\]. The potential difference developed between the ends of the wing having a span of 25 m, if the earth's magnetic field at the location has a magnitude of \[5\times {{10}^{-4}}T\] and the dip angle is \[30{}^\circ \] is:

    A) \[4.125\,\,V\]

    B) \[3.125\,\,V\]  

    C) \[2.225\text{ }V\]                      

    D) \[3.8\text{ }V\]

    Correct Answer: B

    Solution :

    (b) \[3.125\,\,V\] Here, \[v=1800\text{ }km\text{ }{{h}^{-1}}=1800\times \frac{5}{18}=500\text{ }m/s\] \[l=25\,m\,{{B}_{H}}=5\times {{10}^{-4}}T,\delta =30{}^\circ \] \[\varepsilon ={{B}_{v}}{{l}_{v}}\], where \[{{B}_{v}}\]= vertical component of earth magnetic field             \[=\left( {{B}_{H}}\sin \,\delta  \right)lv\] \[=5\times {{10}^{-4}}\times sin\,\,30{}^\circ \times 25\times 500\] \[=31250\times {{10}^{-4}}=3.125\,\,V\]


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