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12th Class Physics Electro Magnetic Induction Question Bank MCQ - Electromagnetic Induction

  • question_answer
    A metal conductor of length 1 m rotates vertically about one of its ends with an angular velocity 5 rad \[{{s}^{-1}}\]. If the horizontal component of earth's magnetic field is \[0.2\times {{10}^{-4}}T\], then the emf developed between the end of the conductor is:

    A) \[5\mu V\]                     

    B) 5 mV   

    C) \[50\mu V\]                   

    D) 50 mV

    Correct Answer: C

    Solution :

    (c) \[50\mu V\] The emf developed between the ends of the conductor is \[\varepsilon =\frac{1}{2}\omega B{{l}^{2}}=\frac{1}{2}\times 5\times 0.2\times {{10}^{-4}}\times {{(1)}^{2}}\] \[=5\times {{10}^{-5}}V=50\times {{10}^{-6}}V=50\mu V\]


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