A) 0.023 V
B) 0.23 V
C) 23 V
D) 230 V
Correct Answer: B
Solution :
(b) 0.23 V Here, \[l=r=5\,cm=5\times {{10}^{-2}}m\] \[\omega =2\pi \left( \frac{1800}{60} \right)rad\,{{s}^{-1}}=60\pi \,\,rad\,\,{{s}^{-1}}\] \[B=1\,Wb\,{{m}^{-2}}\] \[\varepsilon =\frac{1}{2}B{{l}^{2}}\omega =\frac{1}{2}\times 1\times {{(5\times {{10}^{-2}})}^{2}}\times 60\pi =0.23\,V\]
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