A) \[{{B}_{0}}{{L}^{2}}Wb\]
B) \[2{{B}_{0}}{{L}^{2}}Wb\]
C) \[\sqrt{2}{{B}_{0}}{{L}^{2}}Wb\]
D) \[4{{B}_{0}}{{L}^{2}}Wb\]
Correct Answer: B
Solution :
(b) \[2{{B}_{0}}{{L}^{2}}Wb\] Here, \[\overrightarrow{B}={{B}_{0}}(\widehat{i}+\widehat{k})T\] Area vector of \[ABCD={{L}^{2}}\widehat{k}\] Area vector \[DEFA={{L}^{2}}\widehat{i}\] Total area vector, \[\overrightarrow{A}={{L}^{2}}(\widehat{i}+\widehat{k})\] Total magnetic flux, \[\phi =\overrightarrow{B}\cdot \overrightarrow{A}\] \[={{B}_{0}}(\widehat{i}+\widehat{k})\cdot {{L}^{2}}(\widehat{i}+\widehat{k})={{B}_{0}}{{L}^{2}}(1+1)=2{{B}_{0}}{{L}^{2}}Wb\]You need to login to perform this action.
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