A) \[{{10}^{-6}}C\]
B) \[2\times {{10}^{-6}}C\]
C) \[8\times {{10}^{-6}}C\]
D) \[2.5\times {{10}^{-6}}C\]
Correct Answer: D
Solution :
(d) \[2.5\times {{10}^{-6}}C\] Magnetic flux \[\phi =B,\,\,A,\] \[\therefore \] change in flux \[\Delta \,\phi =B.\,dA\] \[\Delta \,\phi =0.05(101-100)\times {{10}^{-4}}\] \[=5\times {{10}^{-6}}Wb\] \[\therefore \] Change in charge \[\Delta Q=\frac{\Delta \phi }{r}=\frac{5\times {{10}^{-6}}}{2}\] \[=2.5\times {{10}^{-6}}C\]
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