A) \[5\times {{10}^{-3}}Wb\]
B) \[4\times {{10}^{-4}}Wb\]
C) \[5\times {{10}^{-4}}Wb\]
D) \[2\times {{10}^{-4}}Wb\]
Correct Answer: C
Solution :
(c) \[5\times {{10}^{-4}}Wb\] Magnetic flux linked with coil \[B,\,\,{{\phi }_{B}}=M{{l}_{A}}\] \[\therefore M=\frac{{{\phi }_{B}}}{{{l}_{A}}}=\frac{{{10}^{-3}}}{4}\text{henry}\] Magnetic flux linked with coil A \[{{\phi }_{A}}=M{{l}_{B}}=\frac{{{10}^{-3}}}{4}\times 2\] \[=5\times {{10}^{-4}}Wb\]
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