question_answer

The charge on \[3\mu F\]capacitor shown in the figure is:

A) \[2\mu C\]                     

B) \[10\,\mu C\]

C) \[6\mu C\]                     

D) \[8\mu C\]

Correct Answer: B

Solution :

(b) Since, all the capacitors are connected in series, therefore, equivalent capacitance is \[\frac{1}{{{C}_{eq}}}=\frac{1}{2}+\frac{1}{3}+\frac{1}{6}=1\] \[\therefore \,\,\,\,\,\,\,\,{{C}_{eq}}=1\mu F\] Charge on each capacitor is same\[\left( \because \,\,V=10\,V \right)\] \[q={{C}_{eq}}V=1\times 10=10\mu C\]