2. Questions Bank
  3. 12th Class
  4. Physics
  5. Electrostatics & Capacitance

12th Class Physics Electrostatics & Capacitance Question Bank MCQ - Electrostatic Potential and Capacitance

  • question_answer
    Three capacitors of capacitances\[1\mu F\], \[2\mu F\]and \[3\mu F\] are connected in series and a potential difference of 11 V is applied across the combination, then the potential difference across the plates of \[1\mu F\]capacitor is:

    A) 2 V                              

    B) 4 V

    C) 1 V                              

    D) 6 V

    Correct Answer: D

    Solution :

    (d) 6V In series combination \[\frac{1}{C}=\frac{1}{{{C}_{1}}}+\frac{1}{{{C}_{2}}}+\frac{1}{{{C}_{3}}}\] \[\Rightarrow \,\,\,\,\,\frac{1}{C}=\frac{1}{1}+\frac{1}{2}+\frac{1}{3}\,\Rightarrow \frac{1}{C}=\frac{6+3+2}{6}\] \[C=\frac{6}{11}\mu F\] Now, \[C=\frac{Q}{V}\] So, \[Q=CV=\frac{6}{11}\times 11=6C\] So, potential difference across \[1\,\mu F\]capacitor is \[V=\frac{Q}{C}=\frac{6}{1}=6V\]


You need to login to perform this action.
You will be redirected in 3 sec spinner